将float转换为int，以便保留所有信息，或者如何获取long float的长度 [英] Transform float to int so that every information is preserved OR how to get the lenght of a long float

问题描述

在Python中，我收到两个浮点数，例如

In Python, I receive two floats e.g.

a = 0.123456
b = 0.012340

和精度

p = 0.000001

告诉我，浮点数的第6个小数后没有数字. 我想将浮点数转换为两个整数，以便它们携带的每个信息都以整数表示.

that tells me there will be no digits beyond the 6th decimal of the floats. I want to transform the floats to two integers, so that every information they carry is represented in the integers.

int_a = 137632
int_b = 12340

在这种情况下，解决方案显然是将它们乘以1000000，但是我想不出一种聪明的方法来达到目标​​. 我尝试通过以下方法获得p中的位数:

The solution in this case is obviously to multiply them by 1000000, but I can't figure out a smart way to get there. I tried the workaround to get the number of digits in p by:

len(str(p))-1 //-1 because of the dot.

但是:

>>> str(p)
>>> 1e-06

好吧，我可以将字符串中的-"替换为"+"并将其转换回浮点数，但这对我来说似乎是一个非常丑陋的方法，我认为必须有一种更简洁，更数学的方法要做到这一点. 有什么建议吗?

Well I could replace the "-" by a "+" in the string and transform it back to a float, but this seems for me to be a pretty ugly approach and I thought there must be a much cleaner, mathematical way to do that. Any suggestion?

推荐答案

为什么不将a和b与1/p相乘?

int(a * 1/p) 
int(b * 1/p)

除了将结果浮点数转换为整数(仅算术-)之外，您完全不需要python(或其字符串方法)

You exactly do not need python (or its string methods) other than converting resulting floats to integer, just arithmetics -))

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