从python中的字符串中删除连续的重复字符 [英] Remove consecutive duplicate characters from a string in python

问题描述

嘿，我试图编写一个程序，该程序将从字符串中删除连续的重复字符.

Hey I was trying to write a program which will remove the consecutive duplicate characters from a string.

例如:
字符串-> aabbccde
第一次迭代:bbccde
第二次迭代:ccde
第三次迭代:de

for example:
string->aabbccde
first iteration: bbccde
second iteration: ccde
third Iteration: de

而德是答案.

以下是我编写的程序.

a = "aabbcs"
def remove_dups(st,ind):
    print st, ind
    st = st.replace(st[ind], "")
    print st, "in dups"
    find_dups(st)

def find_dups(text):
    s=text
    print s, "in find"
    ln = len(s)
    print ln
    fg = 0
    ind = 0
    if ln==1:
        print s, 'len'
        return s
    for i in range(0,ln-1):
        if(s[i]==s[i+1]):
            ind = i
            remove_dups(s,ind)
    print s, 'check'        
    return s

ans = find_dups(a)
print 'answer', ans

以下是我得到的输出

查找中的aabbcs
6
aabbcs 0
英国广播公司成对的
bbcs在find
4
bbcs 0
cs in dups
查找中的cs
2
cs check
bbcs检查
aabbcs 2
AAC APS
查找中的AAC
4
aacs 0
cs in dups
查找中的cs
2
cs check
AAC检查
aabbcs检查
回答aabbcs

aabbcs in find
6
aabbcs 0
bbcs in dups
bbcs in find
4
bbcs 0
cs in dups
cs in find
2
cs check
bbcs check
aabbcs 2
aacs in dups
aacs in find
4
aacs 0
cs in dups
cs in find
2
cs check
aacs check
aabbcs check
answer aabbcs

在上面，我们已经得到了cs，但是答案仍然是原始字符串，我可以理解这是由于递归，但是无法理解如何解决该问题.一点帮助将不胜感激.谢谢！

here above we have got cs but still answer is coming original string, I can understand it is because of recursion, but unable to understand how to resolve the issue. A little help would be appreciated. Thanks!

推荐答案

您的行remove_dups(s,ind)是问题.它不对返回的值做任何事情.如果您仔细阅读了代码，则在顶层函数调用中，将在顶部分配s=text，然后在底部返回s，而无需修改s的值.提示是，在打印正确答案后，您将最后打印原始文本.
尝试s = remove_dups(s, ind)

Your line remove_dups(s,ind) is the problem. It's not doing anything with the returned value. If you read through your code, in the top level function call you're assigning s=text at the top, then returning s at the bottom, without ever modifying the value of s. The clue is that you're printing the original text last, after you've printed the correct answer.
Try s = remove_dups(s, ind)

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