搜索重复元素数组 [英] search duplicate element array

问题描述

这项工作:

arr[0]="XX1 1"
arr[1]="XX2 2" 
arr[2]="XX3 3"
arr[3]="XX4 4"
arr[4]="XX5 5"
arr[5]="XX1 1"
arr[6]="XX7 7"
arr[7]="XX8 8"

duplicate() { printf '%s\n' "${arr[@]}" | sort -cu |& awk -F: '{ print $5 }'; }

duplicate_match=$(duplicate)

echo "array: ${arr[@]}"

# echo "duplicate: $duplicate_match"

[[ ! $duplicate_match ]] || { echo "Found duplicate:$duplicate_match"; exit 0; }

echo "no duplicate"

使用相同的代码，此代码不起作用，为什么?

with same code, this one doesn't work, why ?

arr[0]="XX"
arr[1]="wXyz" 
arr[2]="ABC"
arr[3]="XX"

推荐答案

要检查重复的代码，此代码要简单得多，并且在两种情况下都可以使用:

To check duplicates this code is much simpler and works in both cases:

uniqueNum=$(printf '%s\n' "${arr[@]}"|awk '!($0 in seen){seen[$0];c++} END {print c}')

(( uniqueNum != ${#arr[@]} )) && echo "Found duplicates"

编辑:要打印副本，请使用以下awk:

To print duplicates use this awk:

printf '%s\n' "${arr[@]}"|awk '!($0 in seen){seen[$0];next} 1'

如果一行不是seen数组的一部分，则

Awk命令存储在数组seen中，然后移至下一行.最后，1仅打印重复的行.

Awk command stores in an array seen if a line isn't already part of seen array and next move to the next line. 1 in the end prints only those lines that are duplicates.

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