需要在启动注册表项中升高的程序(Windows 7) [英] Program needing elevation in Startup registry key (windows 7)

问题描述

我有一个要在计算机启动时运行的程序.我已将其路径放入"SOFTWARE \ Microsoft \ Windows \ CurrentVersion \ Run"中.这是在Windows 7中.当计算机启动时，没有任何反应.我在想这是因为程序在运行时需要提升.但是Windows不要求提升权限，也没有提供任何反馈.它只是忽略它.我读过Vista告诉您该程序已被阻止等.有人知道Windows 7为什么只是忽略该应用程序吗?

I have a program that I'd to run when the computer starts. I've put its path inside "SOFTWARE\Microsoft\Windows\CurrentVersion\Run". This is in Windows 7. When the computer starts nothing happens. I'm thinking this is because the program needs elevation when I run it. But Windows does not ask for permission to elevate and gives no feedback. It simply ignores it. I've read that Vista tells you that the program was blocked etc. Does anybody have any idea why Windows 7 simply ignores the application?

非常感谢您.

Alireza

推荐答案

Windows Vista和7阻止程序需要从启动进行提升，以防止每次启动时出现大量的UAC提示. UAC小组的博客条目对此进行了解释很清楚.解决方法是，如果您的程序绝对必须以提升的特权运行，请创建一个任务计划程序条目以启动程序.

Windows Vista and 7 block programs requiring elevation from startup to prevent a flurry of UAC prompts at each startup. This blog entry from the UAC team explains it pretty clearly. As a workaround, create a task scheduler entry to start the program if your program absolutely must run with elevated privileges.

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