以askopenfilename选择的字符串获取文件目录 [英] Get a file's directory in a string selected by askopenfilename

问题描述

我正在制作一个程序，您可以使用askopenname文件对话框选择一个文件，然后将其保存到字符串中，以便可以使用另一个函数(已经完成)将文件提取到一个文件中.预定的其他位置. 我打开文件对话框的按钮代码是:

I'm making a program that you use the askopenname file dialog to select a file, which I then want to save the directory to a string so I can use another function (which I already made) to extract the file to a different location that is predetermined. My button code that opens the file dialog is this:

`a = tkinter.Button(gui, command=lambda: tkinter.filedialog.askopenfilename(initialdir='C:/Users/%s' % user))`

推荐答案

这应该是您想要的:

import tkinter
import tkinter.filedialog
import getpass
# Need this for the `os.path.split` function
import os
gui = tkinter.Tk()
user = getpass.getuser()
def click():
    # Get the file
    file = tkinter.filedialog.askopenfilename(initialdir='C:/Users/%s' % user)
    # Split the filepath to get the directory
    directory = os.path.split(file)[0]
    print(directory)
button = tkinter.Button(gui, command=click)
button.grid()
gui.mainloop()

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