带变量的Gforth条件表达式-仅部分正确 [英] Gforth conditional expression with variables - only partly correct

问题描述

简单表达式:

variable x  ok
4 x !  ok
3 x < . -1  ok
3 x > . 0  ok

但这似乎是正常且正确的:

This seems normal and correct, however:

variable x  ok
3 x !  ok
x 4 < . 0  ok
x 4 > . -1  ok

第二个代码块是错误的.什么是错误的评估?这是什么问题?

The second block of code is wrong. What is evaluating wrongly? What is the problem here?

推荐答案

variable x创建新变量，但是x返回地址，而不是值.

variable x makes a new variable, but x returns the address, not the value.

您需要这样的东西:

variable x
3 x !  ok
x @ 4 < .
x @ 4 > .

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