MbUnit:比较双打的最优雅方法是什么? [英] MbUnit: The most elegant way to compare doubles?

问题描述

代码

Assert.AreEqual (9.97320998018748d, observerPosition.CenterLongitude);

产生

Expected Value & Actual Value : 9.97320998018748
Remark : Both values look the same when formatted but they 
are distinct instances.

在MbUnit 3.0中比较两个双精度是否相等的最优雅方法是什么?我知道我可以自己将它们四舍五入，但是为此有一些MbUnit构造吗?

更新:我认为我当前的解决方法"不佳:

Assert.LessThan(
   Math.Abs(9.97320998018748d - observerPosition.CenterLongitude),
   0.0000001);

解决方案

AreApproximatelyEqual 似乎是为此的MbUnit构造":

验证实际值 大约等于一些预期 值在指定的增量内.

这似乎类似于 Assert.AreEqual(double expected, double actual, double delta)

The code

Assert.AreEqual (9.97320998018748d, observerPosition.CenterLongitude);

produces

Expected Value & Actual Value : 9.97320998018748
Remark : Both values look the same when formatted but they 
are distinct instances.

What is the most elegant way to compare two doubles for equality in MbUnit 3.0? I know I could round them up myself, but is there some MbUnit construct for this?

UPDATE: I consider my current "workaround" to be non-elegant:

Assert.LessThan(
   Math.Abs(9.97320998018748d - observerPosition.CenterLongitude),
   0.0000001);

解决方案

AreApproximatelyEqual seems to be the "MbUnit construct for this":

Verifies that an actual value approximately equals some expected value to within a specified delta.

This seems to be similar to Assert.AreEqual(double expected, double actual, double delta)

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