Websphere:如何将Uri添加到plugin-cfg.xml的UriGroup中 [英] Websphere: How to add a Uri to UriGroup of plugin-cfg.xml

问题描述

我是Websphere的新手. 我们已经在Websphere应用程序服务器(8.5.5)上安装了一个简单的hello world应用程序，并且将ibm http服务器的上下文根设置为/HelloWorld. 下面给出的是我们用于战争的web.xml:

I am new to Websphere. We have installed a simple hello world app on the websphere application server (8.5.5) and with ibm http server with the context root set as /HelloWorld. Given below is the web.xml we are using for the war:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    id="WebApp_ID" version="3.0">
    <display-name>HelloWorld</display-name>
    <servlet>
        <servlet-name>welcome</servlet-name>
        <jsp-file>/index.jsp</jsp-file>
    </servlet>
    <servlet-mapping>
        <servlet-name>welcome</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

</web-app>

当我浏览到http:///HelloWorld时，我希望看到我的hello world应用程序的index.jsp页面的内容. 但是，我得到了禁止"页面.如果使用路径http:///HelloWorld/index.jsp

When I browse to http:///HelloWorld I am expecting to see the contents of the index.jsp page of my hello world application. However I am getting the "Forbidden" page. I see the contents if I use the path http:///HelloWorld/index.jsp

一些在线帖子/文档将我带到服务器上的plugin-cfg.xml文件. 我已经编辑了文件，以手动将Uri"/HelloWorld/*"添加到默认的URIGroup，并且可以正常工作.

Some posts/documentation online lead me to plugin-cfg.xml file on the server. I have edited the file to add the Uri "/HelloWorld/*" to the default URIGroup manually and it works.

现在我的问题是如何使用管理控制台将Uri添加到UriGroup? 还有一种方法可以通过部署战争来添加路由，而不用显式地编辑plugin-cfg文件.

Now my question is how do I add a Uri to the UriGroup using the Adminsitration Console? Also is there a way to have the route added via the war being deployed instead of editing the plugin-cfg file explicitly.

更新: 现在可以正常工作了，我假设在部署过程中将模块映射到群集(将模块映射到服务器"步骤)将自动将其映射到Web服务器，但显然不是.我已经将该模块映射到群集和Web服务器，并且可以正常工作，我将再次从头开始重做整个部署，以确保我的理解是正确的，然后更新该帖子.

Update: It's working now I assumed that mapping the module to the Cluster during deployment ("Map modules to servers" step) will automatically map it to the web server, but apparently not. I have mapped the module to the cluster and the web server and it works I will just redo the whole deployment from scratch again to make sure my understanding is correct and then update the post.

感谢@dbreaux

Thanks @dbreaux

更新#1

我想我应该使用RTFI(I =指令).部署页面上就可以解决我的问题.

I guess I should RTFI (I = Instruction). The fix for my issue was right there on the deployment page.

将模块映射到服务器
指定目标，例如应用程序服务器 或要在其中安装应用程序服务器的群集 应用程序中包含的模块.模块可以是 安装在同一应用程序服务器上或分散在多个应用程序中 应用程序服务器. 另外，将Web服务器指定为目标 **用作请求此应用程序的路由器.插件 **为每个Web服务器生成配置文件(plugin-cfg.xml)， 基于路由的应用程序.

Map modules to servers
Specify targets such as application servers or clusters of application servers where you want to install the modules that are contained in your application. Modules can be installed on the same application server or dispersed among several application servers. Also, specify the Web servers as targets that **serve as routers for requests to this application. The plug-in **configuration file (plugin-cfg.xml) for each Web server is generated, based on the applications that are routed through.

推荐答案

因此，首先，应该由web.xml进行一定的处理，而不是通过编辑plugin-cfg.xml来处理.

So, first, this should be handled by web.xml for certain, not by editing plugin-cfg.xml.

我怀疑如果将<url-pattern>更改为'/*'，它将按预期工作.但是我希望'/'也能正常工作，因为那是默认"映射.请参阅 Servlet映射网址格式中/和/*之间的差异

I suspect if you change your <url-pattern> to '/*', it will work as you expect. But I'd have expected '/' to work as well, as that's the "default" mapping. See Difference between / and /* in servlet mapping url pattern

但是，根据您要尝试执行的操作，可能会有更常规的方法来执行此操作.例如，web.xml提供了<welcome-file-list>元素，您可以在其中定义在请求纯上下文根时要提供的URL.

Depending on what you're trying to do, though, there might be more normal ways to do it. For instance, web.xml provides a <welcome-file-list> element where you define what URL you want provided when the plain context-root is requested.

您也完全不需要为JSP明确定义<servlet>元素. WebSphere会自动理解这些内容.

You also don't need to explicitly define <servlet> elements for JSPs at all. Those are understood automatically by WebSphere.

因此，在您的情况下，这应该足够了:

So in your case, this should be sufficient:

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <display-name>HelloWorld</display-name>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
</web-app>

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