如何捕获异步void方法异常? [英] How to catch async void method exception?

问题描述

我有一个这样的实现:

Task<IEnumerable<Item1>> GetItems1() 
{
    return RunRequest(async () => ParseItemsFromResponse(await(httpClient.Get(..))));
}

Task<IEnumerable<Item2>> GetItems2() 
{
    return RunRequest(async () => ParseItemsFromResponse(await httpClient.Get(..)));
}


TResult RunRequest<TResult>(Func<TResult> req)
{
    try
    {
        return req();
    }
    catch (Exception ex)
    {
        // Parse exception here and throw custom exceptions
    }
}

问题是无效的匿名方法async () => ParseItemsFromResponse(..).

The issue is the void anonymous method async () => ParseItemsFromResponse(..).

由于它返回void而不是Task，因此，如果在匿名方法中引发异常，则实际上不会被RunRequest中的try和catch捕获.

Since it returns void and not a Task, if there's an exception thrown within the anonymous method, it's actually not going to be caught by the try and catch within the RunRequest.

有什么建议可以重构吗?

Any suggestions how to refactor this?

推荐答案

RunRequest应该采用Func<Task<TResult>>，例如:

async Task<TResult> RunRequestAsync<TResult>(Func<Task<TResult>> req)
{
  try
  {
    return await req().ConfigureAwait(false);
  }
  catch (Exception ex)
  {
    // Parse exception here and throw custom exceptions
  }
}

然后将您的async lambda转换为async Task<T>方法而不是async void.

Then your async lambdas are converted to async Task<T> methods instead of async void.

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