延迟任务 [英] Delay in a task

问题描述

无法获得任务延迟.
同步完全不会延迟.
异步停止在await Task.Delay(delay);.

Cannot get a Delay in a task.
The Sync does not delay at all.
The Async stops at await Task.Delay(delay);.

我尝试过:

Task wait4me = Task.Delay(1000);
await wait4me;

并且不起作用-停在await wait4me;.

Task<int> TaskOfTResult_MethodSync(int delay)
{
    Debug.WriteLine($"TaskOfTResult_MethodSync delay = {delay}  {DateTime.Now}");
    int hours = 10; 
    Task.Delay(delay);
    Debug.WriteLine($"TaskOfTResult_MethodSync after delay  {DateTime.Now}");
    return Task.FromResult(hours);
}
async Task<int> TaskOfTResult_MethodAsync(int delay)
{
    Debug.WriteLine($"TaskOfTResult_MethodAsync  delay = {delay}   {DateTime.Now}");
    await Task.Delay(delay);
    Debug.WriteLine($"After await Task.Delay({delay})  {DateTime.Now}");
    int hours = 11;
    return hours;
}

测试

Task<int> task = TaskOfTResult_MethodSync(1000);
Debug.WriteLine("before task.Wait");
task.Wait();
Debug.WriteLine("after  task.Wait");
int i = task.Result;
Debug.WriteLine($"i = {i}");
Debug.WriteLine($"");


Task<int> taskA = TaskOfTResult_MethodAsync(1000);
Debug.WriteLine("before taskA.Wait");
taskA.Wait();
Debug.WriteLine("after  taskA.Wait");
i = taskA.Result;
Debug.WriteLine($"i = {i}");
Debug.WriteLine($"");

推荐答案

您可以简单地通过

Task.Delay(delay).Wait()

这篇关于延迟任务的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！