Python:将2个有序列表组合成元组列表 [英] python: combine 2 ordered lists into list of tuples

问题描述

我有2个列表，我想合并为一个元组列表，以便保持顺序，并且result[i]是(first[i], second[i]).假设两个列表的大小始终相同.有没有一种方法可以使用列表推导?例如:

I have 2 lists that I want to combine into a single list of tuples, so that order is maintained and the result[i] is (first[i], second[i]). Assume that the two lists will always be of the same size. Is there a way to do this using list comprehension? So for example:

>>> first = [1,2,3]
>>> second = [4,5,6]
>>> combine(first, second)
[(1,4), (2,5), (3,6)]

我尝试了一些事情

[(i,j) for i in first, j in second]
[(i for i in first, j for j in second)]
[(i,j) for i,j in first, second]

这些都不起作用.我只是想知道这是否可行，或者是否必须使用循环来实现.

None of these work. I'm just wondering if this is possible or if I have to do it using a loop.

推荐答案

使用邮政编码:

list(zip(first, second))
Out[384]: [(1, 4), (2, 5), (3, 6)]

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