检查List< List< int>>包含List< int> [英] Check if List<List<int>> Contains List<int>

问题描述

检查List<List<int>>是否包含List<int>的最佳方法是什么:

What is the best way to check if a List<List<int>> contains a List<int> like:

List<List<int>> test = new List<List<int>>();
List<int> a = new List<int>{1,2,3,4,5,6};
List<int> b = new List<int>{1,2,3,4,5,6};
test.Add(a);
Debug.Log(test.Contains(b));

我知道Contains()不会检查List<T>的内容，所以我正在寻找一种确定等效性的替代方法.

I know that Contains() doesn't check the contents of List<T>, so I'm looking for an alternative way to determine equivalence.

推荐答案

尝试一下:

test.Any(x => x.All(b.Contains));

这将返回true，但并不完全正确.如果b包含的元素多于1,2,3,4,5,6(例如，7,8,9等)，它也会返回true.要解决此问题，您可以尝试SequenceEqual:

This will return true but it's not exactly correct. It would also return true if b contains more elements than 1,2,3,4,5,6 (for example 7,8,9, etc). To fix this you can try SequenceEqual:

test.Any(x => x.OrderBy(y => y)
    .SequenceEqual(b.OrderBy(z => z)));

如果您不希望它在b无序(例如2,1,3,4,5,6)无序时返回true，则不要使用OrderBy；否则，请使用OrderBy.只需使用SequenceEqual:

If you don't want it to return true when b is unordered (for example 2,1,3,4,5,6), then don't use OrderBy; just use SequenceEqual:

test.Any(x => x.SequenceEqual(b));

这篇关于检查List< List< int>>包含List< int>的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！