Python检查多个列表的相似性 [英] Python Checking Multiple Lists For Similarities

问题描述

例如，我有3个列表

list1=['Oh','My','god','I','A','List!']

list2=['Oh','What','You','Dramatic?']

Keyword=['I','Dunno','What','You','Talking','About','DOT']

编辑

我想分别比较列表1和2的关键字.它将变成:

I Want to compare keywords with list 1 and 2 separately. so it would become:

编辑

common=['What','I','You']

如果我有10个以上的列表怎么办? <-可选问题.

What if i had more than 10 lists? <-- optional question.

推荐答案

由于您的评论表明您希望项目同时存在于Keyword和 >或list2，您可能不希望三者相交.相反，您应该获取list1和list2的并集，然后获取该结果与Keyword的交集.

Since your comment indicates that you want items that exist in both Keyword and either list1 or list2, you probably don't want an intersection of all three. Instead you should get the union of list1 and list2, and then get the intersection of that result and Keyword.

类似以下内容应该可以为您提供所需的内容:

Something like the following should give you what you want:

common = list((set(list1) | set(list2)) & set(Keyword))

或者是一种更具扩展性的替代方法(感谢Karl的简化版):

Or an alternative approach that is more extensible (thanks to Karl for the shortened version):

lists = [list1, list2, list3, list4, list5, list6, list7, list8, list9, list10]
common = list(set().union(*lists).intersection(Keyword))

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