Python:将一个列表中的值匹配到另一列表中的值序列 [英] Python: matching values from one list to the sequence of values in another list

问题描述

真的需要帮助.我对循环感到困惑，撞到了砖墙.

Really need help. I've confused myself with loops and hit a brick wall.

我有两个列表.

 e_list = [('edward', '1.2.3.4.'), ('jane','1.2.3.4.'), ('jackie', '2.3.4.10.')...]

和a_list(要检查的主要列表)

and a_list (the main list to be checked against)

 a_list = [('a', '1.2.3.'), ('b', '2.3.'), ('c', '2.3.4.')...]

我的问题:我想将 e_list 中数字的数字与 a_list 中数字的最短序列进行匹配.这样， new_list 的格式应类似于:

My problem: I want to match the digits in the numbers in e_list to the shortest sequence of the numbers in a_list. So that new_list is formed to look like:

 new_list = [ ('edward', '1.2.3.4', '1.2.3'), ('jane', '1.2.3.4.', '1.2.3'), ('jackie', '2.3.4.10.', '2.3.')...]

我目前所做的(不多，我知道)是:

What I've currently done (not much, I know) is:

for e in e_list:
    e_key = e[1]
    for a in a_list:
        a_key = a[1]
        if a_key in e_key:
            print a_key, "in"

这是在检查 a_list 的编号是否在 e_list 的编号中.但是然后它为所有序列打印出输入"，例如对于b和c，jackie都计入in，而我希望它是最短的值b.我现在正为下一步工作而苦苦挣扎.任何帮助，将不胜感激.预先谢谢你.

What this is doing is checking if the numbers of a_list are in those of e_list. But then it's printing out "in" for all sequences e.g. jackie is counted as in for both b and c, whereas I want it to be the shortest value, b. I'm struggling now with what the next step is. Any help would be appreciated. Thankyou in advance.

推荐答案

for name, digits in e_list:
    shortest = sorted([d for l, d in a_list if digits.startswith(d)], key=len)[0]
    print name, digits, shortest

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