比较C#中不同类型的列表 [英] compare different type of list in c#

问题描述

我有两个列表，一个是字符串列表，另一个是一个类的列表.该类包含一些属性，例如soid，itemname，qty等，其值也..string列表和类列表具有一些公共属性.so我想要检查带有类列表的字符串列表，并将公用值添加到一个字典中.

i have two list one is string list and other one is list of one class.that class contain some properties like soid,itemname,qty etc and its value also..string list and class list have some common property .so i wanted to check the string list with class list and add common values to one dictionary.

public class Input
   {
       public string soid { get; set; }

       public string itemname { get; set; }

       public int qty { get; set; }
   }
list<Input> inputclass=new  list<Input>();//inputclass list

List<string> metadata=new List<string>();//string list
metadata.Add("itemname");
        metadata.Add("soid");
        metadata.Add("qty");

所以我想将类成员名称与字符串列表名称进行比较

so i wanted to compare the class member name with string list name

推荐答案

如果我理解正确，那么您想比较类型本身，而不是列表中的实例.

If I understood it right, you want to compare the type itself, not the instances inside that list.

您可以这样操作:

List<string> metadata = new List<string>();//string list
metadata.Add("itemname");
metadata.Add("soid");
metadata.Add("qty");
metadata.Add("yada");

var result = from str in metadata
             join prop in typeof(Input).GetProperties() on str equals prop.Name
             select str;

foreach (string prop in result)
{
    Console.WriteLine(prop);
}

现在，如果您有一个T个未知对象的列表，并且希望将每个对象与元数据进行匹配，请告诉我，我会为您提供帮助.

Now, if you have a List of T unknown objects and want to match each with the metadata, tell me and I'll help you.

编辑:when we get the common name between list<input> and string how will get the value of corresponding member of the class.now you return only common names r8..?

您可以这样做.假设您有以下两个类:

You could do it like this. Suppose you have these two classes:

public class Input
{
    public string soid { get; set; }

    public string itemname { get; set; }

    public int qty { get; set; }
}

public class Yada : Input
{
    public string yada { get; set; }
}

所以Input具有4个属性中的3个，而Yada类具有所有4个属性.

So Input has 3 of the 4 properties, and Yada class has all 4.

然后假设我们有一个对象列表:

Then suppose we have a list of objects:

List<Input> inputclass = new List<Input>();//inputclass list

inputclass.Add(new Input() { itemname = "test",soid="myId",qty=10 });
inputclass.Add(new Yada() { itemname = "test2",soid="myId2", yada = "woo",qty=20 });

您可以使用以下代码从对象中获取所有匹配的属性，包括它们的当前值:

You could get all the matching properties from the objects, including their current values, with this code:

var result = inputclass.Select(
                 input => (from str in metadata
                           join prop in input.GetType().GetProperties()
                           on str equals prop.Name
                           select new { Obj = input, Prop = str, Value = prop.GetValue(input, null) }))
                           .SelectMany(i => i)
                           .GroupBy(obj => obj.Obj);

foreach (var obj in result)
{
    Console.WriteLine(obj.Key);
    foreach (var prop in obj)
    {
        Console.WriteLine(prop.Prop + ":" + prop.Value);
    }
    Console.WriteLine();
 }

 Console.ReadKey();

这是我的输入内容:

仅需注意，使用GetValue时要小心:例如，您必须对其进行一些细微更改才能与Indexers一起使用.

Just on a note, be careful when using GetValue: you'll have to do slight changes for it to work with Indexers, for example.

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