检查Python中连续相等元素的数量 [英] Check the number of consecutive equal elements in Python

问题描述

我的目的是确定给定字符串或列表中连续相等元素的最大数量.

My purpose is to determine the maximum number of consecutive equal elements in a given string or list.

我将通过一个例子来使自己更加清楚:

I'll try to be more clear using an example:

(1,1,1,1)-> {1:4}

(1,1,1,1) -> {1:4}

(1,1，'a'，'a'，1)-> {1:2，'a':2}

(1,1,'a','a',1) ->{1:2, 'a':2}

(2,2,2,0,2,2,0)-> {2:3，0:1}

(2,2,2,0,2,2,0) -> {2:3, 0:1}

我对类似的东西感到厌倦，但它不起作用:

I have tired with something like that but it does not work:

d={}
for i in range(len(l)):
    while l[i]==l[i+1]:
        d[i]=l.count(i)
return d

推荐答案

使用 groupby 方法:

Another solution here, using itertools' groupby method:

from itertools import groupby

l = [2,2,2,0,2,2,0]
elems = list(set(l))
g = [{elem : max([len(list(g)) for k,g in groupby(l) if elem == k])} for elem in elems]
print(g)

结果:

[{0: 1}, {2: 3}]

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