将列表转换为Prolog中的术语 [英] Converting list to terms in Prolog
问题描述
我必须实现谓词cons(List, Term)
,该谓词将使用列表[Head|Tail]
并将其转换为表示为next(Head, Tail)
的术语.我该怎么做呢?我什至不知道从哪里开始.
I have to implement the predicate cons(List, Term)
that will take a list [Head|Tail]
and convert it to terms, represented as next(Head, Tail)
. How do I do this? I don't even know where to start.
以下是问题中给出的成功查询的示例:
Here is the example of a successful query given in the question:
cons([a,b,c],X). /*query returns X=next(a,next(b,next(c,null))).*/
推荐答案
对列表执行大多数操作都将需要考虑两种情况:空列表以及带有标题和子列表的列表.通常,您的基本案例处理空列表,而归纳案例处理带有子列表的列表.
Doing most anything with lists will require that you consider two cases: the empty list and a list with a head and a sublist. Usually your base case is handling the empty list and your inductive case is handling the list with sublist.
首先考虑您的基本情况:
First consider your base case:
cons([], null).
现在处理您的归纳案件:
Now deal with your inductive case:
cons([X|Xs], next(X, Rest)) :- cons(Xs, Rest).
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