将两个嵌套列表中的项目连接成元组对 [英] Concatenate items in two nested lists to pairs in tuples

问题描述

我有两个嵌套列表:

ls1 = [["a","b"], ["c","d"]]
ls2 = [["e","f"], ["g","h"]]

我想要以下结果[(a，e)，(b，f)，(c，g)，(d，h)]

and I'd like the following result [(a,e), (b,f), (c,g), (d,h)]

我尝试使用zip(a，b)，如何将嵌套列表压缩到具有元组对的列表中?

I've tried zip(a,b), how do I zip nested lists into a list with tupled pairs?

推荐答案

您还可以使用 itertools.chain.from_iterable 和zip:

>>> ls1 = [["a","b"], ["c","d"]]
>>> ls2 = [["e","f"], ["g","h"]]
>>> 
>>> zip(itertools.chain.from_iterable(ls1), itertools.chain.from_iterable(ls2))
[('a', 'e'), ('b', 'f'), ('c', 'g'), ('d', 'h')]

这篇关于将两个嵌套列表中的项目连接成元组对的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！