如何使用fmt在Go中打印出常量uint64? [英] How can I print out an constant uint64 in Go using fmt?

问题描述

我尝试过:

fmt.Printf(％d"，math.MaxUint64)

fmt.Printf("%d", math.MaxUint64)

但是我收到以下错误消息:

but I got the following error message:

常数18446744073709551615溢出int

constant 18446744073709551615 overflows int

我该如何解决?谢谢！

推荐答案

math.MaxUint64是常量，而不是int64.尝试尝试:

math.MaxUint64 is a constant, not an int64. Try instead:

fmt.Printf("%d", uint64(num))

这里的问题是常量没有类型.该常数将根据其使用的上下文采用一种类型.在这种情况下，它被用作接口{}，因此编译器无法知道您要使用哪种具体类型.对于整数常量，默认为int.由于您的常量溢出一个int，因此这是一个编译时错误.通过传递uint64(num)，您是在通知编译器您希望将该值视为uint64.

The issue here is that the constant is untyped. The constant will assume a type depending on the context in which it is used. In this case, it is being used as an interface{} so the compiler has no way of knowing what concrete type you want to use. For integer constants, it defaults to int. Since your constant overflows an int, this is a compile time error. By passing uint64(num), you are informing the compiler you want the value treated as a uint64.

请注意，此特定常数仅适用于uint64，有时仅适用于uint.该值甚至大于标准int64可以容纳的值.

Note that this particular constant will only fit in a uint64 and sometimes a uint. The value is even larger than a standard int64 can hold.

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