如何检查对象是否是namedtuple的实例? [英] How to check if an object is an instance of a namedtuple?

问题描述

如何检查对象是否为推荐答案

调用函数 collections.namedtuple会为您提供一个新类型，它是tuple的子类(没有其他类)，带有一个名为_fields的成员，它是一个元组，其项均为字符串.因此，您可以检查以下每一项:

Calling the function collections.namedtuple gives you a new type that's a subclass of tuple (and no other classes) with a member named _fields that's a tuple whose items are all strings. So you could check for each and every one of these things:

def isnamedtupleinstance(x):
    t = type(x)
    b = t.__bases__
    if len(b) != 1 or b[0] != tuple: return False
    f = getattr(t, '_fields', None)
    if not isinstance(f, tuple): return False
    return all(type(n)==str for n in f)

有可能从中得到误报，但前提是有人要竭尽全力地创建看起来像命名元组的 lot 但不是一个元组的类型；-)

it IS possible to get a false positive from this, but only if somebody's going out of their way to make a type that looks a lot like a named tuple but isn't one;-).

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