如何防止java.lang.String.split()创建前导空字符串? [英] How to prevent java.lang.String.split() from creating a leading empty string?

问题描述

将0用作限制参数可以防止尾随空字符串，但是如何防止前导空字符串?

passing 0 as a limit argument prevents trailing empty strings, but how does one prevent leading empty strings?

例如

String[] test = "/Test/Stuff".split("/");

结果为包含"，测试"，填充"的数组.

results in an array with "", "Test", "Stuff".

是的，我知道我可以使用自己的令牌生成器...但是StringTokenizer的API文档说

Yeah, I know I could roll my own Tokenizer... but the API docs for StringTokenizer say

"StringTokenizer是一个遗留类，为保持兼容性而保留 原因，尽管在新代码中不鼓励使用它.推荐 任何寻求此功能的人都会使用拆分"

"StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split"

推荐答案

您最好的选择可能就是删除任何领先的分隔符:

Your best bet is probably just to strip out any leading delimiter:

String input = "/Test/Stuff";
String[] test = input.replaceFirst("^/", "").split("/");

您可以通过以下方法使其更通用:

You can make it more generic by putting it in a method:

public String[] mySplit(final String input, final String delim)
{
    return input.replaceFirst("^" + delim, "").split(delim);
}

String[] test = mySplit("/Test/Stuff", "/");

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