如何在Java中测试类是否正确实现了Serializable(不仅是Serializable的实例) [英] how to test in Java that a class implements Serializable correctly (not just is an instance of Serializable)

问题描述

我正在实现一个可序列化的类(因此它是一个用于RMI的值对象).但是我需要测试一下.有办法轻松做到这一点吗?

I am implementing a class to be Serializable (so it's a value object for use w/ RMI). But I need to test it. Is there a way to do this easily?

说明:我正在实现该类，因此将Serializable保留在类定义中很简单.我需要手动对其进行序列化/反序列化，以查看其是否有效.

clarification: I'm implementing the class, so it's trivial to stick Serializable in the class definition. I need to manually serialize/deserialize it to see if it works.

我发现了这个 C#问题 ，对于Java有类似的答案吗?

I found this C# question, is there a similar answer for Java?

推荐答案

最简单的方法是检查对象是否是java.io.Serializable或java.io.Externalizable的实例，但这并不能真正证明该对象确实是可序列化.

The easy way is to check that the object is an instance of java.io.Serializable or java.io.Externalizable, but that doesn't really prove that the object really is serializable.

唯一可以确定的方法是实际尝试.最简单的测试是这样的:

The only way to be sure is to try it for real. The simplest test is something like:

new ObjectOutputStream(new ByteArrayOutputStream()).writeObject(myObject);

并检查它是否不会引发异常.

and check it doesn't throw an exception.

Apache Commons Lang 提供了一个更为简短的版本:

Apache Commons Lang provides a rather more brief version:

SerializationUtils.serialize(myObject);

再次检查异常.

您仍然可以更加严格，并检查它反序列化为与原始序列相同的内容:

You can be more rigourous still, and check that it deserializes back into something equal to the original:

Serializable original = ...
Serializable copy = SerializationUtils.clone(original);
assertEquals(original, copy);

以此类推.

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