正则表达式获取字符串中其他字符的第一个数字 [英] Regex to get first number in string with other characters

问题描述

我是正则表达式的新手，我想知道如何只获取字符串中的第一个数字，例如100 2011-10-20 14:28:55.在这种情况下，我希望它返回100，但是数字也可以更短或更长时间.

I'm new to regular expressions, and was wondering how I could get only the first number in a string like 100 2011-10-20 14:28:55. In this case, I'd want it to return 100, but the number could also be shorter or longer.

我在考虑类似[0-9]+之类的东西，但是它将每个单独的数字分开(100,2001,10，...)

I was thinking about something like [0-9]+, but it takes every single number separately (100,2001,10,...)

谢谢.

推荐答案

尝试以下操作以匹配字符串中的第一个数字(不能位于字符串的开头):

Try this to match for first number in string (which can be not at the beginning of the string):

    String s = "2011-10-20 525 14:28:55 10";
    Pattern p = Pattern.compile("(^|\\s)([0-9]+)($|\\s)");
    Matcher m = p.matcher(s);
    if (m.find()) {
        System.out.println(m.group(2));
    }

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