如何从番石榴列表中获取max()元素 [英] How to get max() element from List in Guava

问题描述

比方说，我们有一套物品:

Let's say we have a Collection of Items:

class Item {
    public String title;
    public int price;
}

List<Item> list = getListOfItems();

我想通过Guava库从列表中获得最高价格的商品(

I would like to get an Item with a maximum price out of that list with Guava library (with Ordering, I presume). I mean something similar to this Groovy code:

list.max{it.price}

我该怎么做?有效率吗?

How do I do that? How efficient is it?

推荐答案

Ordering<Item> o = new Ordering<Item>() {
    @Override
    public int compare(Item left, Item right) {
        return Ints.compare(left.price, right.price);
    }
};
return o.max(list);

效率最高:遍历列表中的项目，并返回价格最高的第一个项目:O(n).

It's as efficient as it can be: it iterates through the items of the list, and returns the first of the Items having the maximum price: O(n).

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