解释一下用JAVA编写的这一行 [英] Explain this line written in JAVA

问题描述

在HACKERRANK中，这行代码非常频繁地出现.我认为这是为了跳过空格，但是"\r\u2028\u2029\u0085"的意思是什么

In HACKERRANK this line of code occurs very frequently. I think this is to skip whitespaces but what does that "\r\u2028\u2029\u0085" thing mean

 scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

推荐答案

Scanner.skip跳过与模式匹配的输入，这里的模式是:-

• ?完全匹配零或前一个字符.
• |替代
• []匹配
中出现的单个字符
• \ r匹配回车符

• \ n换行符

• ? matches exactly zero or one of the previous character.
• | Alternative
• [] Matches single character present in
• \r matches a carriage return

• \n newline

\ u2028将字符与区分大小写的索引2018 base 16(8232 base 10或20050 base 8)匹配

\u2028 matches the character with index 2018 base 16(8232 base 10 or 20050 base 8) case sensitive

第一种替代方法\ r \ n

1st Alternative \r\n

• \ r与回车符(ASCII 13)匹配
• \ n与换行符(ASCII 10)匹配

第二个替代项[\ n \ r \ u2028 \ u2029 \ u0085]

2nd Alternative [\n\r\u2028\u2029\u0085]

• 匹配[\ n \ r \ u2028 \ u2029 \ u0085]下面列表中存在的单个字符
• \ n与换行符(ASCII 10)匹配
• \ r与回车符(ASCII 13)匹配
• \ u2028从字面上(区分大小写)LINE SEPARATOR匹配具有索引202816(823210或200508)的字符
• \ u2029从字面上将字符与索引202916(823310或200518)相匹配(区分大小写)PARAGRAPH SEPARATOR
• \ u0085从字面上(区分大小写)将索引为8516(13310或2058)的字符与下一行匹配
• Match a single character present in the list below [\n\r\u2028\u2029\u0085]
• \n matches a line-feed (newline) character (ASCII 10)
• \r matches a carriage return (ASCII 13)
• \u2028 matches the character with index 202816 (823210 or 200508) literally (case sensitive) LINE SEPARATOR
• \u2029 matches the character with index 202916 (823310 or 200518) literally (case sensitive) PARAGRAPH SEPARATOR
• \u0085 matches the character with index 8516 (13310 or 2058) literally (case sensitive) NEXT LINE

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