带SimpleDateFormat的Java解析日期 [英] Java Parse Date w/ SimpleDateFormat

问题描述

我确定这是一个简单的方法！ 我已经将此字符串String date = "Wed, 2 Jan 2013 12:17:15 +0000 (GMT)"解析为Date，以便能够设置JavaMail的发送日期.

I'm sure this is a simple one! I've got this String String date = "Wed, 2 Jan 2013 12:17:15 +0000 (GMT)" which I want to parse to a Date to be able to set an JavaMail's sent date.

这是我的完整代码

String dateString = "Wed, 2 Jan 2013 12:17:15 +0000 (GMT)";
SimpleDateFormat sdf = new SimpleDateFormat("EEE, d MMM yyyy HH:mm:ss Z");
Date date = sdf.parse(dateString);
System.out.println("Date: " + date.toString());
email.setSentDate(oDate); // Assume email is initialised correctly

预期产量

Date: Wed, 2 Jan 2013 12:17:15 +0000 (GMT)

实际输出

Date: Wed Jan 02 12:17:15 GMT 2013

只要我的电子邮件似乎来自正确的日期，我甚至都不会为时间问题烦恼.

I'm not even bothered about the time component, as long as my email appears to be from the correct date.

推荐答案

尝试一下:

String reformattedStr = sdf.format(sdf.parse(dateString));

或这个

String reformattedStr = sdf.format(sdf.parse(date.toString()));

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