通过电子邮件发送Spark DataFrame [英] Sending a Spark DataFrame via Email
本文介绍了通过电子邮件发送Spark DataFrame的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在从事这个项目,我需要在spark数据框中获取表数据并通过邮件发送.使用的语言是Scala.
I am working on this project where I need to get the table data in a spark dataframe and send it in a mail. The language to be used is Scala.
用于保存表数据的数据框如下:-
The dataframe to hold the table data is as follows:-
val sqlDfUT = hiveCon.sql("select * from UserTable")
我需要在邮件中将"sqlDfUT"作为消息正文发送.
I need to send "sqlDfUT" as a message body in a mail.
发送邮件的代码是:
sendScalaMail("monitor@foo.com","Users Data Sent : \n " + sqlDfUT +
",\nMail sent from host: " + java.net.InetAddress.getLocalHost().getHostName(),
"12525","Hive Data Checking completed for given User: 12525" )
def sendScalaMail (mailSender:String, strMailBody:String, mailIdList:String, strMailSubj:String)={
if ((mailIdList == null) && (mailIdList.equals(""))){
writeToLog("Email ID not defined")
}
writeToLog("<----Sender---->"+mailSender)
writeToLog("<----strMailBody---->"+strMailBody)
writeToLog("<----mailIdList---->"+mailIdList)
writeToLog("<----strMailSubj---->"+strMailSubj)
val smtpHost:String = "mail.foo.com"
val prop:Properties = new Properties()
prop.put("mail.smtp.host", smtpHost)
prop.put("mail.debug", "false")
var session:Session = Session.getInstance(prop)
var toPersonList:Array[String] = mailIdList.split(",")
var toMailListSB:StringBuffer = new StringBuffer()
var toPersonName:String = ""
var toMailId:String = ""
var index:Int = 0
for(index <- 0 to toPersonList.length){
toPersonName = toPersonList(index).asInstanceOf[String]
toMailId = toPersonName+"@mail.foo.com"
toMailListSB.append(toMailId)
toMailListSB.append(";")
}
try{
var msg:MimeMessage = new MimeMessage(session)
msg.setFrom(new InternetAddress(mailSender))
var toList:Array[String] = toMailListSB.toString().split(",")
var address:Array[InternetAddress] = new InternetAddress(toList.length.toString()).asInstanceOf[Array[InternetAddress]]
var i:Int = 0
for(i <- 0 to toList.length){
address(i) = new InternetAddress(toList(i))
}
msg.setRecipients(Message.RecipientType.TO, address)
msg.setHeader("Content-Type", "text/html")
msg.setSubject(strMailSubj)
msg.setSentDate(new Date())
msg.setContent(strMailBody, "text/html")
Transport.send(msg)
}
catch{
case me:MessagingException =>{
me.printStackTrace()
writeToLog("<---Error in method sendScalaMail--->"+me)
}
} }
但是,我在行中得到了错误
However, I am getting the error in line
msg.setRecipients(Message.RecipientType.TO, address)
,错误消息是
overloaded method value setRecipients with alternatives: (x$1: javax.mail.Message.RecipientType,x$2: String)Unit <and> (x$1: javax.mail.Message.RecipientType,x$2: Array[javax.mail.Address])Unit cannot be applied to (javax.mail.Message.RecipientType, Array[javax.mail.internet.InternetAddress])
如果能得到任何指导,我将感到非常高兴.谢谢
I will be really glad if I could get any guidance. Thank you
推荐答案
var address:Address = new InternetAddress(toMailId).asInstanceOf[Address]
这对我有用!!谢谢拉斐尔:)
this worked for me!! Thank you Raphael :)
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