像Xpath一样查询嵌套的python字典 [英] Xpath like query for nested python dictionaries

问题描述

有没有一种方法可以为嵌套的python字典定义XPath类型查询.

Is there a way to define a XPath type query for nested python dictionaries.

类似这样的东西:

foo = {
  'spam':'eggs',
  'morefoo': {
               'bar':'soap',
               'morebar': {'bacon' : 'foobar'}
              }
   }

print( foo.select("/morefoo/morebar") )

>> {'bacon' : 'foobar'}

我还需要选择嵌套列表;)

I also needed to select nested lists ;)

这可以通过@jellybean的解决方案轻松完成:

This can be done easily with @jellybean's solution:

def xpath_get(mydict, path):
    elem = mydict
    try:
        for x in path.strip("/").split("/"):
            try:
                x = int(x)
                elem = elem[x]
            except ValueError:
                elem = elem.get(x)
    except:
        pass

    return elem

foo = {
  'spam':'eggs',
  'morefoo': [{
               'bar':'soap',
               'morebar': {
                           'bacon' : {
                                       'bla':'balbla'
                                     }
                           }
              },
              'bla'
              ]
   }

print xpath_get(foo, "/morefoo/0/morebar/bacon")

这个问题和被接受的答案都是古老的.更新的答案可能比原始答案做得更好.但是我没有测试它们，所以我不会更改已接受的答案.

This question and the accepted answer are ancient. The newer answers may do the job better than the original answer. However I did not test them so I won't change the accepted answer.

推荐答案

不是很漂亮，但是您可能会使用

Not exactly beautiful, but you might use sth like

def xpath_get(mydict, path):
    elem = mydict
    try:
        for x in path.strip("/").split("/"):
            elem = elem.get(x)
    except:
        pass

    return elem

当然，这不支持xpath之类的索引，更不用说了/键陷阱unutbu了.

This doesn't support xpath stuff like indices, of course ... not to mention the / key trap unutbu indicated.

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