jQuery:查找具有特定类的最后一个孩子 [英] jQuery: find a last child that has specific class

问题描述

如果我有深层嵌套的无序列表，并且有对根节点的引用，是否有一种内置方法来查找具有特定css类的"li"类型的最后一个子级?例如，如果我有一个树视图分支，深度为5级，并且分支向下扩展到第三级，则1,2,3级将具有可折叠"类.现在，在这种情况下，我想在第3级上找到具有此类的最后一个"li".

If I have deep nested unordered list and I have a reference to the root node, is there a built in way to find a last child of "li" type that has specific css class? For example if I have a tree view branch 5 levels deep, and branch is expanded down to thrid level, levels 1,2,3 will have a class "collapsable". Now I want to find a last "li" in this case on level 3 that has this class.

推荐答案

不太难:

$("li.someclass", rootOfList).last()

在类someclass

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