功能完成后检查 [英] Check once a function is complete

问题描述

单击链接以赋予漫画风格效果时，我加载的div的偏移量很小.每个偏移量都会激活其他动画，以提供更动态的感觉.

I have a lit of offsets for a div that I load when a link is clicked to give a comic book style effect. Each offset activates other animations to give a more dynamic feel.

我现在正在寻求对其进行更改，以便从偏移量0偏移到偏移量2将通过偏移量1移动.要增加复杂性，我不希望在这种情况下关闭偏移量1的辅助动画.

I am now looking to change it so that to move from offset 0 to offset 2 will move via offset 1. To add to the complexity, I don't want the secondary animations at offset 1 to go off in this instance.

因此，问题是我需要激活滑动功能，然后在当前功能完成后再次激活它.有什么办法让我知道吗?另外，是否有一种简单的方法可以反转动画，以便动画在下次到达该偏移时发生?

The problem, therefore, is that I need to activate the sliding function and then activate it again once the current one is complete. Is there a way for me to know this? Also, is there an easy way to reverse the animation so it will occur the next time they go to that offset?

如果我使用错误的方法，请随时告诉我.

If I am going about this the wrong way, please feel free to tell me.

推荐答案

看来，您问题的核心是javascript代码流.您将要使用回调函数.如果您向函数添加回调变量，则可以在函数运行其过程之后执行代码:

It seems that the core of your problem is the flow of the javascript code. You will want to use a callback function. If you add a callback variable to a function, you can execute code after the function has run its course:

function foo(callback) {
    // some code you want to execute

    // then run the callback function
    if (typeof(callback) == "function")
        callback();
}

function bar() {
   // some code you want to execute after foo is finished
}

现在，您可以在foo完成后像这样运行bar():

Now you can run bar() after foo is complete like this:

foo(bar);

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