jQuery ajax发布成功返回数据 [英] jquery ajax post success return data
本文介绍了jQuery ajax发布成功返回数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我无法取回数据,这是我的代码.问题出在哪儿?谢谢.
I can not get back my data, here is my code. where is the problem? Thanks.
Index.php
Index.php
<script type="text/javascript">
jQuery(document).ready(function(){
$(".click").click(function(){
var value = $(this).val();// post each click value to another page
$.ajax({
url: "post.php",
dataType: "html",
type: 'POST', //I want a type as POST
data: "name="+value,
success: function(data){
$("#result").data($data);
}
});
});
});
</script>
<div id="result"></div>
<a href="#" class="click">tim</a>
<a href="#" class="click">tom</a>
<a href="#" class="click">jimmy</a>
post.php
<?php
$name=trim(addslashes(htmlspecialchars(rawurldecode($_POST["name"]))));
$data .='Your name is '.$name;
$data .='how do you do';
echo $data;// how to return all the html in post.php? or return $data part?
?>
推荐答案
看到问题了吗?
...
success: function(data){
$("#result").data($data);
}
...
您将数据视为data
,但尝试将其作为$data
访问,这是一个不同的未初始化变量.
You take the data as data
but try to access it as $data
, which is a different, uninitialized variable.
此外,您不能在a
元素上使用.val()
,而是使用.html()
来获取内部HTML.您可能还想在#result
上使用.html()
代替.data()
.
Also, you cannot use .val()
on an a
element, use .html()
instead to get the inner HTML. You probably want to use .html()
instead of .data()
on #result
also.
否则,您的示例似乎还可以.
Otherwise your example seems all right.
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