基于对象中其他值的对象总和 [英] Sum values of objects based on other values in object

问题描述

我有一个对象，格式如下:

I have an object, the format is such:

let obj= {
  'Jan 01': [
             {dt: 'Jan 01', cat: 'abc', site: 'google', val1:10, val2:20, val3:30},
             {dt: 'Jan 01', cat: 'abc', site: 'bing', val1:23, val2:12, val3:14},
             {dt: 'Jan 01', cat: 'abc', site: 'jeeves', val1:67, val2:78, val3:12},
             {dt: 'Jan 01', cat: 'pqr', site: 'google', val1:10, val2:20, val3:30},
             {dt: 'Jan 01', cat: 'pqr', site: 'bing', val1:23, val2:12, val3:14},
             {dt: 'Jan 01', cat: 'pqr', site: 'jeeves', val1:67, val2:78, val3:12},
             {dt: 'Jan 01', cat: 'xyz', site: 'google', val1:10, val2:20, val3:30},
             {dt: 'Jan 01', cat: 'xyz', site: 'bing', val1:23, val2:12, val3:14},
             {dt: 'Jan 01', cat: 'xyz', site: 'jeeves', val1:67, val2:78, val3:12}
            ],
  'Feb 01': [
             {dt: 'Feb 01', cat: 'abc', site: 'google', val1:12, val2:11, val3:41},
             {dt: 'Feb 01', cat: 'abc', site: 'bing', val1:45, val2:67, val3:0},
             {dt: 'Feb 01', cat: 'abc', site: 'jeeves', val1:78, val2:34, val3:41},
             {dt: 'Feb 01', cat: 'pqr', site: 'google', val1:44, val2:88, val3:5},
             {dt: 'Feb 01', cat: 'pqr', site: 'bing', val1:56, val2:11, val3:99},
             {dt: 'Feb 01', cat: 'pqr', site: 'jeeves', val1:22, val2:34, val3:77},
             {dt: 'Feb 01', cat: 'xyz', site: 'google', val1:33, val2:99, val3:34},
             {dt: 'Feb 01', cat: 'xyz', site: 'bing', val1:77, val2:55, val3:14},
             {dt: 'Feb 01', cat: 'xyz', site: 'jeeves', val1:33, val2:23, val3:98}
            ],
  'Mar 01': [
             {dt: 'Mar 01', cat: 'abc', site: 'google', val1:11, val2:20, val3:6},
             {dt: 'Mar 01', cat: 'abc', site: 'bing', val1:22, val2:91, val3:89},
             {dt: 'Mar 01', cat: 'abc', site: 'jeeves', val1:33, val2:81, val3:12},
             {dt: 'Mar 01', cat: 'pqr', site: 'google', val1:44, val2:71, val3:33},
             {dt: 'Mar 01', cat: 'pqr', site: 'bing', val1:55, val2:61, val3:14},
             {dt: 'Mar 01', cat: 'pqr', site: 'jeeves', val1:66, val2:51, val3:43},
             {dt: 'Mar 01', cat: 'xyz', site: 'google', val1:77, val2:41, val3:98},
             {dt: 'Mar 01', cat: 'xyz', site: 'bing', val1:88, val2:31, val3:23},
             {dt: 'Mar 01', cat: 'xyz', site: 'jeeves', val1:99, val2:21, val3:4}
            ]
}

我想基于对象内部的2个值对val1的值求和.我想对基于dt和cat的值求和.

I want to sum the values of val1, based on 2 of the values inside my object. I want to sum the values based on dt and cat.

我知道如何根据键求和:

I know how to sum the values based on the keys:

    let group = Object.entries(obj).map(([key, group]) => ({
          ['dt']: key, // because it is similar to the key
          ['val1']: group.map(entry => entry[val1]).reduce((pv, cv) => {
                    return pv + (parseFloat(cv) || 0);,
          ['val2']: group.map(entry => entry[val2]).reduce((pv, cv) => {
                    return pv + (parseFloat(cv) || 0);,
          ['val3']: group.map(entry => entry[val3]).reduce((pv, cv) => {
                    return pv + (parseFloat(cv) || 0);,            
    }));

如何基于dt和cat求和?我需要我的最终值是:

How do I sum based on dt and cat? I need my final value to be:

let obj= {
  'Jan 01': [
             {dt: 'Jan 01', cat: 'abc', val1:100, val2:110, val3:56},
             {dt: 'Jan 01', cat: 'pqr', val1:100, val2:110, val3:56},
             {dt: 'Jan 01', cat: 'xyz', val1:100, val2:110, val3:56},   
             ],
  'Feb 01': [
             {dt: 'Feb 01', cat: 'abc', val1:135, val2:112, val3:82},
             {dt: 'Feb 01', cat: 'pqr', val1:122, val2:133, val3:181},
             {dt: 'Feb 01', cat: 'xyz', val1:143, val2:177, val3:146}
            ],
  'Mar 01': [
             {dt: 'Mar 01', cat: 'abc', val1:66, val2:192, val3:107},
             {dt: 'Mar 01', cat: 'pqr', val1:165, val2:183, val3:90},
             {dt: 'Mar 01', cat: 'xyz', val1:264, val2:93, val3:125}
            ]
}

甚至dt和site.

我希望能够基于2个值进行分组.有可能吗?

I want to be able to group based on 2 values. Is that possible?

推荐答案

在

Use dt+','+cat as a key in a Map to track dupes. sum up all the other keys.
assumes any keys other than site dt and cat are vals.

for(const key of Object.keys(obj)) {
  const catMap = new Map()
  for(const {site, dt, cat, ...vals} of obj[key]) {
    const row = catMap.get(dt+','+cat)||{dt, cat}
    Object.entries(vals).forEach(([k,v])=>row[k]=(row[k]||0)+v)
    catMap.set(dt+','+cat, row)
  }
  obj[key] = [...catMap.values()]
}

console.log(
  obj
)

<script>
let obj= {
  'Jan 01': [
             {dt: 'Jan 01', cat: 'abc', site: 'google', val1:10, val2:20, val3:30},
             {dt: 'Jan 01', cat: 'abc', site: 'bing', val1:23, val2:12, val3:14},
             {dt: 'Jan 01', cat: 'abc', site: 'jeeves', val1:67, val2:78, val3:12},
             {dt: 'Jan 01', cat: 'pqr', site: 'google', val1:10, val2:20, val3:30},
             {dt: 'Jan 01', cat: 'pqr', site: 'bing', val1:23, val2:12, val3:14},
             {dt: 'Jan 01', cat: 'pqr', site: 'jeeves', val1:67, val2:78, val3:12},
             {dt: 'Jan 01', cat: 'xyz', site: 'google', val1:10, val2:20, val3:30},
             {dt: 'Jan 01', cat: 'xyz', site: 'bing', val1:23, val2:12, val3:14},
             {dt: 'Jan 01', cat: 'xyz', site: 'jeeves', val1:67, val2:78, val3:12}
            ],
  'Feb 01': [
             {dt: 'Feb 01', cat: 'abc', site: 'google', val1:12, val2:11, val3:41},
             {dt: 'Feb 01', cat: 'abc', site: 'bing', val1:45, val2:67, val3:0},
             {dt: 'Feb 01', cat: 'abc', site: 'jeeves', val1:78, val2:34, val3:41},
             {dt: 'Feb 01', cat: 'pqr', site: 'google', val1:44, val2:88, val3:5},
             {dt: 'Feb 01', cat: 'pqr', site: 'bing', val1:56, val2:11, val3:99},
             {dt: 'Feb 01', cat: 'pqr', site: 'jeeves', val1:22, val2:34, val3:77},
             {dt: 'Feb 01', cat: 'xyz', site: 'google', val1:33, val2:99, val3:34},
             {dt: 'Feb 01', cat: 'xyz', site: 'bing', val1:77, val2:55, val3:14},
             {dt: 'Feb 01', cat: 'xyz', site: 'jeeves', val1:33, val2:23, val3:98}
            ],
  'Mar 01': [
             {dt: 'Mar 01', cat: 'abc', site: 'google', val1:11, val2:20, val3:6},
             {dt: 'Mar 01', cat: 'abc', site: 'bing', val1:22, val2:91, val3:89},
             {dt: 'Mar 01', cat: 'abc', site: 'jeeves', val1:33, val2:81, val3:12},
             {dt: 'Mar 01', cat: 'pqr', site: 'google', val1:44, val2:71, val3:33},
             {dt: 'Mar 01', cat: 'pqr', site: 'bing', val1:55, val2:61, val3:14},
             {dt: 'Mar 01', cat: 'pqr', site: 'jeeves', val1:66, val2:51, val3:43},
             {dt: 'Mar 01', cat: 'xyz', site: 'google', val1:77, val2:41, val3:98},
             {dt: 'Mar 01', cat: 'xyz', site: 'bing', val1:88, val2:31, val3:23},
             {dt: 'Mar 01', cat: 'xyz', site: 'jeeves', val1:99, val2:21, val3:4}
            ]
}
</script>

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