对行进行分组和分页计数 [英] Counting Rows for Grouping and Paging

问题描述

在尝试对页面行进行下一页和下一页时，我有以下代码

I have the following code where I am trying to pagenext and previous for table rows

$( "a.paginate" ).click( function( e ) {
e.preventDefault();
if ( $( this ).attr( "id" ) == "next" ) {
//what to write here? 
// firstrecord should be between 0 and max rows
// somehow page size has to be added to the firstrecord
} else {
//what to write here?
// pagesize has to be subtracted, but unable to figure how to
}
paginate( firstRecord, pageSize );
});

http://jsfiddle.net/99xAU/1/

有人可以帮我整理一下使代码正常工作的方法吗

Can anybody help me sort how to make the code work

推荐答案

您可以使用 slice :

You can use slice:

描述:将匹配元素的集合简化为指定的子集 通过一系列指标.

Description: Reduce the set of matched elements to a subset specified by a range of indices.

定义要在当前页面中显示的元素.

to define the elements to display in the current page.

代码:

var firstRecord = 0;
var pageSize = 4;
var tableRows = $("#movie tbody tr");

$("a.paginate").click(function (e) {
    e.preventDefault();
    var tmpRec = firstRecord;
    if ($(this).attr("id") == "next") {
        tmpRec += pageSize;
    } else {
        tmpRec -= pageSize;
    }
    if (tmpRec < 0 || tmpRec > tableRows.length) return
    firstRecord = tmpRec;
    paginate(firstRecord, pageSize);
});

var paginate = function (start, size) {
    var end = start + size;
    tableRows.hide();
    tableRows.slice(start, end).show();
}


paginate(firstRecord, pageSize);

演示: http://jsfiddle.net/H9JBT/

对于隐藏/显示下一个/上一个按钮，您可以使用 :visible 和 is .

For hide/show next/prev button you can check if the first/last element in visible using :visible and is.

代码:

var paginate = function (start, size) {
    var end = start + size;
    tableRows.hide();
    tableRows.slice(start, end).show();
        $(".paginate").show();
    if (tableRows.eq(0).is(":visible")) $('#previous').hide();
        if (tableRows.eq(tableRows.length-1).is(":visible")) $('#next').hide();
}

演示: http://jsfiddle.net/IrvinDominin/LPwVB/

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