如何在JSON中使用JS变量? [英] How do I use a JS variable within JSON?

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本文介绍了如何在JSON中使用JS变量?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试创建一个邮政编码查询JQuery脚本,该脚本将能够在页面上多次使用,而不必为页面上的每个地址重复该脚本. 查找"按钮具有类"postcodeLookup"和属性地址",这就是我打算如何使脚本填充正确的地址(它使用JQuery Populate插件)的方式.输入的名称为address [line1],其中"address"是可更改的(家庭[line1],office [line1]等).

I'm attempting to create a postcode lookup JQuery script that'll be able to be used multiple times on a page, without having to duplicate the script for every address on the page. The Find button has the class "postcodeLookup" and the attribute "address" which is how I intended to get the script to populate the right address (it uses JQuery Populate plugin) & the inputs are named address[line1], where "address" is changeable (home[line1], office[line1], etc.).

问题是如何获取填充地址的JSON以使用变量内容而不是原义字词"address"?

The problem is how to get the JSON that populates the address to use the variable contents rather than the literal word "address"?

//postcode lookups
$(".postcodeLookup").click(function(){
    alert("I am The Postcode Finder...\nPretending to find the address...\nFound it!");
    var address = $(this).attr('address');
    $("form").populate({
        address: {
            line1: "First Line of Addr.",
            line2: "Line 2!",
            line3: "Line 3 of The Address",
            postcode: "PO1 1PO"
        }
    });
    $(".addressArea").slideDown('fast');
});

推荐答案

var addrName = "office";
var address = {};

address[ addrName ] = {
   line1: "First line",
   line2: "Line 2..."
};

$("form").populate( address );

现在,当addrNameoffice时,这与书写相同

Now, when addrName is office, that will be the same as writing

address['office'] = { }

...与写作完全相同

address.office = { }

那一点点知识对javascript的各个方面都是非常有用的.

And that little piece of knowledge will be immensely useful in all aspects of javascript.

例如

for(var i = 0; i < 10; i++) {
    window['var' + i] = i;
}

实际上会在窗口对象中创建10个变量,即var0var1,...,var9.

Will actually create 10 variables in the window object (i.e. public variables) called var0, var1, ..., var9.

好吧,这不是很有用,但是您明白了.

Ok, so that wasn't immensely useful, but you get the idea.

这篇关于如何在JSON中使用JS变量?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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