如何在一个字符串中搜索第二个字符串中包含的所有单词? [英] How to search one string for all of the words contained in a second string?

问题描述

我需要检查 string A 是否匹配，具体取决于它是否包含另一个 string B 中的所有单词-顺序是否相同.

I need to check a string A for a match based on whether it contains all of the words in another string B - in whatever order.

因此，假设 string A 是这样的:

So, let's say string A is this:

one two three four five

string B 是其中之一:

And string B is one of these:

one two three // match!
one three two // match! (order doesn't matter)
one two six // NOT A MATCH! ('six' is not found in string A)
one two three four // match!
one two three four five // match!
one two three four five seven // NOT A MATCH! ('seven' is not found in string A)

仅当在 string B 中找到每个单词时，才能找到 string A 和 string B 之间的匹配项strong> string A (无论两个字符串中单词的顺序如何，并且无论 string A 是否包含在 string B 中都找不到的其他单词)?

How would I find a match between string A and string B only if every word in string B is found in string A (regardless of the order of the words in either string and regardless of whether string A contains additional words that are not found in string B)?

我不知道jQuery是否具有任何对此有帮助的特殊功能，或者我是否需要严格使用纯JavaScript?

I don't know if jQuery has any special features that would help with this or whether I need to do it strictly with pure JavaScript?

推荐答案

//如果客户端具有数组方法 every ，则此方法非常有效-

// If the client has the array method every, this method is efficient-

function commonwords(string, wordlist){
    string= string.toLowerCase().split(/\s+/);
    wordlist= wordlist.toLowerCase().split(/\s+/);
    return wordlist.every(function(itm){
        return string.indexOf(itm)!= -1;
    });
}

常用词(一二三四有五"，一二有九")；

//如果您希望任何客户端在没有特殊功能的情况下进行处理， 您可以解释"高级数组方法-

// If you want any client to handle it without a special function, you can 'explain' the advanced array methods-

Array.prototype.every= Array.prototype.every || function(fun, scope){
    var L= this.length, i= 0;
    if(typeof fun== 'function'){
        while(i<L){
            if(i in this && !fun.call(scope, this[i], i, this)) return false;
            ++i;
        }
        return true;
    }
    return null;
}
Array.prototype.indexOf= Array.prototype.indexOf || function(what, i){
    i= i || 0;
    var L= this.length;
    while(i< L){
        if(this[i]=== what) return i;
        ++i;
    }
    return -1;
}

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