验证网址而不使用www.或http:// [英] validate url without www. or http://

问题描述

我正在寻找一个URL.我已经有一个脚本来验证不允许www.和http://，但是我还需要验证.co.uk .com等.

I'm looking to validate an URL. I have already a script that validates to not allow www. and http:// but i need to also validate for .co.uk .com etc.

如果输入example.co.ukff之类的内容，我的脚本将无法运行.

My script won't run if they enter something like example.co.ukff.

我有一个完整的URL:

I have this for a full URL:

^[a-zA-Z]+[:\/\/]+[A-Za-z0-9\-_]+\\.+[A-Za-z0-9\.\/%&=\?\-_]+$/i

我只需要验证结尾.co.uk或.com等.

I just need to validate the end .co.uk or .com etc.

推荐答案

尝试一下...

/^http:\/\/|(www\.)?[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?$/

它完全可以满足您的需求.

It's working exactly what you want.

需要带或不带http://, https://,和www.

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