如何使用jquery和json访问特定的json对象? [英] How can I access a specific json object using jquery and json?

问题描述

我在尝试使用jQuery和JSON返回特定记录时遇到问题.我正在将一个变量传递给该函数，并且只希望输出与执行该函数时设置的ID匹配的数据.

I'm having a problem trying to return a specific record using jQuery and JSON. I'm passing a variable to the function and want to output only the data matching the id I've set when the function is executed.

现在，我的功能如下:

function getEffectsData(myNum){
    $.getJSON("jsonscript.php", { id: +myNum },function(data){
       var x = data.x;
       //DO SOME STUFF
    });
}

JSON输出如下:

{"stuff": [ { "id":1, "x":3, "y":6, "z":-6 },{ "id":2, "x":2, "y":7, "z":-3 }]}

我唯一知道的是正确的变量正在传递给函数.在那之后，什么都没有发生.这是非常新的，因此，非常感谢您的帮助.

The only thing I know is that the correct variable is being passed to the function. After that, nothing happens. Very new at this, so any help is greatly appreciated.

感谢大家对此的投入.为了澄清，我试图仅从id与myNum匹配的对象返回数据.我希望能够访问该对象中的所有数据，但只能访问该对象.我不知道该对象将在数组中的哪个位置.我简化了问题中的ID和数据，以帮助澄清问题.

I appreciate everybody's input on this. To clarify, I am trying to return the data from only the object that's id matches myNum. I want to be able to access all of the data from that object, but only that object. I have no idea where that object will be in the array. I simplified the ids and the data in my question to help clarify the problem.

再次感谢.

推荐答案

您可以像这样从JSON访问x:

You can access x from your JSON like this:

var x1 = data.stuff[0].x; // the first object's x key
var x2 = data.stuff[1].x; // the second object's x key

因为您的JSON树如下所示:

Because your JSON tree looks like this:

{ // base object
    "stuff": [ // array
    { // 0.: object
        "id": 1,  // key => value
        "x" : 3,  // key => value
        "y" : 6,  // key => value
        "z" : -6  // key => value
    },
    { // 1.: object
        "id": 2,  // key => value
        "x" : 2,  // key => value
        "y" : 7,  // key => value
        "z" : -3  // key => value
    }]
}

因此，在data.stuff[0].x中选择stuff对象，然后选择first元素，然后选择其x键.

So with data.stuff[0].x you select stuff object then it's first element and then its x key.

但是，例如，如果要处理所有x键，则需要通过简单的for循环或

But If you want to handle all the x key for example, then you need to loop through the stuff array by a simple for loop or the $.each method.

更新

关于您的问题.如果要获取ID为myNum的对象，则有 2种可能性:

As for your question. If you want to get the object with id myNum you have 2 possibilities:

1. 如果拥有jsonscript.php，则只能从服务器发送具有正确ID的数据，因为您通过{ id: +myNum }将ID传递给它，这是

1. if you possess jsonscript.php you can send the data only with the correct id from the server, because you pass the id to it by { id: +myNum } which is the second parameter of getJSON

您将遍历数据，直到找到具有正确ID的对象

You loop through the data until you find the object with the correct id

var object; 
$.each(data.stuff, function(i, obj) {
  if (obj.id === myNum) object = obj;
});
// now object is the one with the right id

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