如何创建动态RegEx [英] How to creat a dynamic RegEx

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本文介绍了如何创建动态RegEx的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试匹配字符串中的某些单词.但是我没有预定义的单词数.

I'm trying to match some words in a string. But I don't have a predefined number of words I need to find.

例如,我在ubuntu-18.10-desktop-amd64.iso.torrent中搜索Ubuntu 18 10会返回true.

For example I search for Ubuntu 18 10 in ubuntu-18.10-desktop-amd64.iso.torrent would return true.

或者我可以在CentOS-7-x86_64-LiveGNOME-1804.torrent中搜索centos 7也会返回true.

Or I could search for centos 7 in CentOS-7-x86_64-LiveGNOME-1804.torrent would also return true.

我不需要检查它是否是小写字母.

I don't need to check if it's lowercase or not.

我尝试过的事情:

$.get('interdit', function(data) {
    var lines = data.split("\n");
    $.each(lines, function(n, data_interdit) {
        var url_check = $('textarea#url').val()
        var split_forbidden = data_interdit.split(/[\s|,|_|.|-|:]+/);
        var exist = 0;
        $.each(split_forbidden, function(n, data) {
            var n = url_check.search("^("+ data +")");
            if(n != -1){
                exist = 1
            }else{
                exist = 0
            }
            console.log('Forbidden: '+ data + ' Result: ' + n);
        })
        if(exist == 1){
            console.log('found')
        }
    });
});

文件 interdit 的示例数据:

CentOS.7
Ubuntu-18

推荐答案

您想在输入字符串中查找现有单词,而无需考虑顺序.为此,您需要使用正向前行:

You want to look for existing words within the input string without the order being taken into account. You need to use positive lookaheads for this:

var search = 'Ubuntu 18 10';
var str = 'ubuntu-18.10-desktop-amd64.iso.torrent';
var re = new RegExp('^(?=.*' + search.split(/[\s,_.:-]+/).join(')(?=.*') + ')', 'i')

console.log(re.test(str));

这将产生如下正则表达式(设置了i标志):

This produces a regex as the following (with i flag set):

^(?=.*Ubuntu)(?=.*18)(?=.*10)

这篇关于如何创建动态RegEx的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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