如何显示基于其他下拉菜单选择的下拉菜单选择的值? [英] How to display a dropdown select based on the value of other dropdown select?

问题描述

假设我有一个下拉选择选项，如下所示:

Suppose I have a dropdown select option like below:

 <form>
    <select name="option" >
                <option value="">Select a Value:</option>
                <option value="1">Option 1</option>
                <option value="2">Option 2</option>

    </select>
</form>

任何用户选择选项1时，我要立即显示以下下拉菜单选择

When any user Selects the Option 1 I want to display the following dropdown select beside it instantly

 <select name="name" >
                <option value="">Select a person:</option>
                <option value="john">john</option>
                <option value="Micheal">Micheal</option>

    </select>

或者，如果有任何用户选择选项2，我想立即显示以下下拉菜单选择

Or, if any user Selects the Option 2 I want to display the following dropdown select beside it instantly

 <select name="class" >
                <option value="">Select a person:</option>
                <option value="Class 1">Class 1</option>
                <option value="Class 2">Class 2</option>

    </select>

请您告诉我该怎么做? 我正在使用Codeigniter.

Would you please kindly show me how to do this? I am using Codeigniter.

推荐答案

$('select[name="option"]').change(function(){
    $('.hidden').hide();
    if(this.value == 1){
        $('select[name="name"]').toggle();
    }
    else if(this.value == 2){
        $('select[name="class"]').toggle();
    }
});

提琴: http://jsfiddle.net/maniator/Z6Upj/

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