匹配两个列表之间的相似元素 [英] matching similar elements in between two lists

问题描述

我是python的新手，所以很抱歉，这是一个愚蠢的问题.

I'm new to python so apologies if its a silly question.

我有两个列表
L1=['marvel','audi','mercedez','honda']和

I have two lists
L1=['marvel','audi','mercedez','honda'] and

L2=['marvel comics','bmw','mercedez benz','audi'].

我想提取包含在list L2中与list L1匹配的匹配元素.所以我做了什么:

I want to extract matching elements which contains in list L2 matched with list L1. So what I done :

for i in L1:
   for j in L2:
       if j in i:
          print (j)

  output is ['audi']

但是，如果元素也包含任何单词匹配，例如mercedez benz中的mercedez和marvel comics中的marvel，我也想返回元素.因此最终输出将是:

But, I also wants to return elements if its also consist any word match like mercedez in mercedez benz and marvel in marvel comics. so final output would be:

j=['audi','mercedez benz','marvel comics']

推荐答案

我认为您真正想要的是L2的元素，其中包含L1中的任何元素.因此，只需将if j in i替换为if i in j:

I think what you really want here is the elements of L2 that contain any elements in L1. So simply replace if j in i with if i in j:

for i in L1:
   for j in L2:
       if i in j:
          print (j)

这将输出:

marvel comics
audi
mercedez benz

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