Kotlin获取没有实例的泛型类的类型 [英] Kotlin get type of generic class without instance

问题描述

嘿要获取 T 的类型，但是我不能从实例中获取它，我必须从类参数中获取它，怎么做?

Hey want go get Type of T , but I can not get it from instance, I have to get it from class parameter, how to do it?

abstract class ViewModelFragment<T : ViewModel>{
    protected lateinit var mViewModel: T

    override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
       mViewModel = ViewModelProviders
                    .of(scope)
                    .get(getGenericTClass())
    // .get(mViewModel.javaClass) // not working either

   }

   inline fun<reified R> getGenericTClass() = R::class.java

}

现在编译器抱怨

不能将'T'用作精致的类类型.改用Class.

Cannot use 'T' as refined class type. Use Class instead.

我尝试使用以下解决方案: https://stackoverflow.com/a/34463352/2163045 但不为我工作

I've tried to use solution of: https://stackoverflow.com/a/34463352/2163045 but not working for me

推荐答案

我遇到了同样的问题，下面的代码帮助了我:

I have the same issue and the code below helped me:

val persistentClass = (javaClass.genericSuperclass as ParameterizedType).actualTypeArguments[0] as Class<T>
mViewModel = ViewModelProvider(this, viewModelsFactory).get(persistentClass)

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