尝试打开多个jframe时数据库被锁定 [英] Database locked while trying to open multiple jframes

问题描述

我的问题是，当我尝试使用该jframe时(例如，将数据插入SQLite Manager的数据库中)，打开一个包含与主jframe信息不同的信息的jframe时.但这给了我数据库锁定错误.我可以从主jframe插入数据，而我正在使用jcombobox打开新的jframe.我想我知道来源，但我不知道如何解决这个问题.我认为我需要关闭我打开其他框架的主jframe.因此，sqlite数据库可以存储这些帧数据.在这里，我将向您介绍如何使用jcombobox打开jframe，以及如何尝试将数据插入数据库.请帮助我或，发表评论您对这个问题的想法.我对来源的想法有误还是对的.我需要你们的帮助.感谢您的阅读.

My problem is , while opening a jframe which is including different informations than my main jframe , when i tried to work on this jframe, for example inserting data to SQLite manager's database . But it's giving me Database locked error.I can insert data from my main jframe which i'm opening new jframes with jcombobox. I hink i know source but i dont know how to fix this. I think i need to close my main jframe which i open other frames. So sqlite database can storage this frames datas. Here i'll give to you how can i open jframes with jcombobox and how i'm trying to insert a data to database. Please help me or , leave a comment what're you thinking about this problem. Am i wrong with source idea or true. I need your helps guys. Thanks for reading.

1:这编码了我如何使用组合框打开jframe.

1: This codes how i'm opening jframes with combobox.

public void comboselect(){

    int d =ComboBox_name.getSelectedIndex();
    if (d==0){
        CezalıUye s=new CezalıUye();
        s.setVisible(true);
        dispose();


    }



    if(d==1){
     DeaktifUye z=new DeaktifUye();
        z.setVisible(true);
               dispose();

    }  
    if(d==2){
     TatbikatForm l=new TatbikatForm();
        l.setVisible(true);
               dispose();

    }    



    }

2:这编码了我试图插入从jcombobox打开的数据的方式.

2:This codes how i'm trying to insert data which i opened from jcombobox.

 private void cmd_saveActionPerformed(java.awt.event.ActionEvent evt) {                                         

        try{
     String sql = "Insert into cezalitablosu (KimTarafından,Kime,Neden,Kaçıncı,Tarih) values (?,?,?,?,?)";

     pst=conn.prepareStatement(sql);
      pst.setString(1, jTextField1.getText());
     pst.setString(2, jTextField2.getText());
  pst.setString(3, jTextField3.getText());
  pst.setString(4, jTextField4.getText());
  pst.setString(5, jTextField5.getText());




     pst.execute();

     JOptionPane.showMessageDialog(null, "Kaydedildi!");

     }   

     catch(Exception e)
     {     
      e.printStackTrace(); 
      JOptionPane.showMessageDialog(null, e);   

     }  



         Update_table();


    }       

推荐答案

execute()不能用于插入，更新和删除.

execute() can not be use for insert,update and delete.

对于插入，更新和删除，始终使用

For insert,update and delete always use

executeUpdate();

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