从基类获取当前的活动名称 [英] Getting current Activity name from base class

问题描述

如何在基类中获取当前活动的名称. 假设我有一个基本活动类BaseActivity:

How can I get the name of the current activity in the base class. Suppose I have a base activity class BaseActivity :

class BaseActivity extends AppCompatActivity
{
    ...
    String getCurrentActivityName() {
            ....
    }
    ...
}

现在我还有另外2个课程

Now I have 2 other classes

class Activity1 extends BaseActivity
{
    ....
}

class Activity2 extends BaseActivity
{
    ....
}

也许还有更多扩展BaseActivity的活动，为简便起见，我在这里使用了2.

There maybe many more activities extending BaseActivity, for brevity I have used 2 here.

我不确定如何在基类中实现getCurrentActivityName()方法.它应该返回一个包含当前活动名称的字符串.

I am not sure how to implement getCurrentActivityName() method in the base class. It should return a String containing the name of the current activity.

由于某些原因，我无法编辑Activity1和Activity2.

EDIT : For some reasons I cannot edit Activity1 and Activity2.

推荐答案

创建新的活动类时，应将类名添加到构造函数中，然后在尝试时使用getCurrentActivityName方法获取它

When creating a new activity class you should add classname to the constructor and then get it with getCurrentActivityName method as you were trying

class BaseActivity extends AppCompatActivity
    {
        protected String className;
        public BaseActivity() { this.className = "BaseActivity"; }
        String getCurrentActivityName() {
              return this.className;
        }
        ...
    }

    class Activity1 extends BaseActivity
    {
        protected String className;
        public Activity1() { this.className = "Activity1"; }
    }

    class Activity2 extends BaseActivity
    {   
        protected String className;
        public Activity2() { this.className = "Activity2"; }

    }

然后致电

BaseActivity baseActivity = new BaseActivity();
baseActivity.getClassname(); // returns "BaseActivity"
Activity1 activity1 = new Activity1();
activity1.getClassname(); // returns "Activity1"

或者，如果您只是想知道当前活动名称，请使用.就这么简单

Or if you just want to know the current activity name use . It's as simple as that

this.getClass().getSimpleName()

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