解开Java清单文件fin bash [英] Unwrapping a java manifest file fin bash

问题描述

在Java中，META-INF/MANIFEST.MF文件具有最大行长.除此之外，还会插入自动换行符，并在下一行的开头用空格表示，如下所示:

In Java, META-INF/MANIFEST.MF files have a maximum line length. Beyond that, an automatic line break is inserted, signaled by a space at the beginning of the next line, like so:

Manifest-Version: 1.0
Export-Package: com.google.common.net;uses:="com.google.common.base,ja
 vax.annotation[file continues]
Bundle-Name: Guava: Google Core Libraries for Java

不幸的是，这使bash中的grep和sed痛苦不堪.

Unfortunately, this makes it painful to grep and sed in bash.

您将如何使用bash将其包装到其中?

How would you go about unwrapping it, using bash, into this?

Manifest-Version: 1.0
Export-Package: com.google.common.net;uses:="com.google.common.base,javax.annotation[file continues]
Bundle-Name: Guava: Google Core Libraries for Java

我会尝试sed，但是它只能在每行的基础上工作，而且我也无法使tr正常工作.

I'd try sed, but it works only on a per line basis, and I can't get tr to work properly either.

谢谢！

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推荐答案

尝试使用此Perl单行代码:

Try this Perl one-liner:

$ perl -0777 -wpe 's/\n //g' MANIFEST.MF

它会删除每个换行符的实例，后跟一个空格.

It removes every instance of a line-break followed by a space.

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