Matlab的内存问题:.mat中的更新变量 [英] Memory issue with Matlab: update variable in .mat

问题描述

我正在Matlab中处理非常计算量大的代码.它要求使用优化技术，并使用很大的矩阵进行长时间的计算.

I am working with a very computational expansive code in Matlab. It requires the usage of optimisation techniques and long computations using very big matrixes.

我遇到了以下问题:即使代码正确运行，在代码要求的迭代结束时，Matlab也不会存储我拥有的最大单元格数组.我猜这是由于我的代码或计算机中的某些内存效率低下(功能可能不够强大).但是，我遵循了Matlab文档中的所有一般建议，但仍然无法正常工作.

I am having the following issue: even if the code run correctly, at the end of the iterations required by the code, Matlab is not storing the biggest cell arrays that I have. I guess that it is due to some memory inefficiency in my code or with my computer (which is probably not sufficiently powerful). However, I followed all the general suggestions in the Matlab documentation and it is still not working.

使用evalc，我设法为代码的每次迭代保存一个不同的变量，以便在循环结束时重新创建原始矩阵.但是，使用:

Using evalc, I managed to save a different variable for each iteration of the code, in order to re-create the original matrix at the end of the loop. However, using:

1. evalc(strcat('var_'，mat2str(i)，'= varTmp'));
2. evalc(strcat('save(var_'，mat2str(i)，'-append)'));
3. clear var *

..以这种方式工作，但是它仍然很慢并且不是很干净整洁".

.. in this way it is working, but it still slow and not very "clean and tidy".

是否有一种更好的方法(考虑到我必须对具有不同名称和维数的几个变量执行相同的操作)还是在更新.mat文件中的单元格数组以添加列的方法? (行或其他)而不加载它?

Is there a way to do the same thing in a better way (consider that I have to do the same thing for several variables with different names and dimensions) or i.e. to update a cell array in a .mat file adding a column (row or whatever) without loading it?

谢谢

推荐答案

使用matfile，它使您可以编写和读取Mat文件的一部分，而无需将其读取到内存中.一个小示范:

Use matfile which allows you writing and reading parts of a mat file without reading it into the memory. A small demonstration:

%initialize matfile
data=matfile('example.mat','writable',true)
n=10
%preallocate cell
data.list=cell(n,1)
for ix=1:n
    %do some stuff
    var=foo(n)
    %store the results
    data.list(3,1)={var}
end

行data.list(3,1)={var}看起来有些奇怪，因为matfile在索引时有一些限制，但是它的含义"是data.list{3}=var.

The line data.list(3,1)={var} looks a little odd because matfile has some limitations when indexing, but it's "meaning" is data.list{3}=var.

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