Java调用方法和使用三元运算符并在参数中赋值? [英] Java calling method and using ternary operator and assign in the parameters?

问题描述

我正在查看一些代码，并且遇到了这个问题:

I was reviewing some code and I came across this:

 public static doSomething(String myString, String myString2) {
        //Stuff
 }

 public static doAnotherThing(String myString) {
      return doSomething(myString = myString != null ? myString.toLowerCase(): myString, null)
 }

这是如何工作的?，我知道将.toLowerCase结果字符串分配给myString(是的，我知道这是不好的作法，因为实际上您不应该重新分配方法参数，因为它们应该是最终的)，但是我不太确定该方法如何始终接收所需的2个参数.

How is this working exactly?, I know the .toLowerCase resulting string is assigned to myString (yes I know bad practice since you are not supposed to reassign method parameters in fact they should be final), but I am not quite sure how does the method always receives the 2 parameters it needs.

我知道myString为null或至少我认为是如何工作的，因为三元数有myString为null，但是我不确定为什么myString不为null时为什么会去那里.

I know how it works when myString is null or at least I think I do, since the ternary has myString, null, but I am not quite sure why it would go there when myString is not null?.

推荐答案

救援的感觉！

doSomething(myString = ( ( myString != null ) ? myString.toLowerCase() : myString ), null)

要了解这一点，您需要了解两件事:

To understand this, you need to know two things:

• 三元运算符的工作原理
• 赋值运算符返回它所赋值的事实

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