有关解析方法签名的正则表达式问题 [英] Regex question about parsing method signature

问题描述

我正在尝试解析这种格式的方法签名:

I'm trying to parse a method signature that is in this format:

'function_name(foo=<str>, bar=<array>)'

由此，我想要方法的名称，每个参数及其类型.显然我不希望<，>字符等.参数的数量将是可变的.

From this, I want the name of the method, and each argument and it's type. Obviously I don't want the <, > characters, etc. The number of parameters will be variable.

我的问题是:使用此正则表达式时如何获取所有参数?我正在使用Python，但我只是在寻找一个一般的想法.我是否需要命名组，如果需要，我如何使用它们来捕获多个参数，每个参数都有其类型，都在一个正则表达式中?

My question is: How is it possible to get all the parameters when using this regex? I'm using Python, but I'm just looking for a general idea. Do I need named groups and, if so, how can I use them to capture multiple parameters, each with it's type, all in one regex?

推荐答案

您无法将可变数量的组与Python正则表达式进行匹配(请参见

You can't match a variable number of groups with Python regular expressions (see this). Instead you can use a combination of regex and split().

>>> name, args = re.match(r'(\w+)\((.*)\)', 'function_name(foo=<str>, bar=<array>, baz=<int>)').groups()
>>> args = [re.match(r'(\w+)=<(\w+)>', arg).groups() for arg in args.split(', ')]
>>> name, args
('function_name', [('foo', 'str'), ('bar', 'array'), ('baz', 'int')])

这将匹配可变数目(包括0)的参数.我选择了不允许额外的空格，但是如果您的格式不是很严格的话，您应该在标识符之间添加\s+来允许它.

This will match a variable number (including 0) arguments. I have chosen not to allow additional whitespace, although you should allow for it by adding \s+ between identifiers if your format isn't very strict.

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