在Axes3D中更改轴的位置 [英] Changing position of axes in Axes3D

问题描述

我正在使用mpl_toolkits库中的mplot3d.在图形上显示3D表面时，我意识到轴的位置没有我希望的那样.

让我展示一下，我在以下屏幕快照中添加了每个轴的位置:

是否有一种方法可以更改轴的位置以获得此结果:

这是工作代码:

import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D

ax = Axes3D(plt.figure())
def f(x,y) :
    return -x**2 - y**2

X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)

# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])

ax.set_yticklabels([-1,1],rotation=-15, va='center', ha='right')

plt.show()

我尝试使用xaxis.set_ticks_position('left')语句，但是它不起作用.

解决方案

没有记录的方法，但是有一些 https://stackoverflow.com/a/15048653/1149007 .

import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D

fig = plt.figure()
ax = ax = fig.add_subplot(111, projection='3d')
ax.view_init(30, 30)


def f(x,y) :
    return -x**2 - y**2

X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)

# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])

ax.xaxis._axinfo['juggled'] = (0,0,0)
ax.yaxis._axinfo['juggled'] = (1,1,1)
ax.zaxis._axinfo['juggled'] = (2,2,2)

plt.show()

我不知道第三个数字以三进制表示的含义.如果设置为零，则图中没有任何变化.因此，应该查看代码以进行进一步的调整.

您还可以查看相关问题更改位置_PLANES属性的低级hacking的3D绘图(Matplotlib)的垂直(z)轴?

I am using mplot3d from the mpl_toolkits library. When displaying the 3D surface on the figure I'm realized the axis were not positioned as I wished they would.

Let me show, I have added to the following screenshot the position of each axis:

Is there a way to change the position of the axes in order to get this result:

Here's the working code:

import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D

ax = Axes3D(plt.figure())
def f(x,y) :
    return -x**2 - y**2

X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)

# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])

ax.set_yticklabels([-1,1],rotation=-15, va='center', ha='right')

plt.show()

I have tried using xaxis.set_ticks_position('left') statement, but it doesn't work.

解决方案

No documented methods, but with some hacking ideas from https://stackoverflow.com/a/15048653/1149007 you can.

import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D

fig = plt.figure()
ax = ax = fig.add_subplot(111, projection='3d')
ax.view_init(30, 30)


def f(x,y) :
    return -x**2 - y**2

X = np.arange(-1, 1, 0.02)
Y = np.arange(-1, 1, 0.02)
X, Y = np.meshgrid(X, Y)
Z = f(X, Y)
ax.plot_surface(X, Y, Z, alpha=0.5)

# Hide axes ticks
ax.set_xticks([-1,1])
ax.set_yticks([-1,1])
ax.set_zticks([-2,0])

ax.xaxis._axinfo['juggled'] = (0,0,0)
ax.yaxis._axinfo['juggled'] = (1,1,1)
ax.zaxis._axinfo['juggled'] = (2,2,2)

plt.show()

I can no idea of the meaning of the third number in triples. If set zeros nothing changes in the figure. So should look in the code for further tuning.

You can also look at related question Changing position of vertical (z) axis of 3D plot (Matplotlib)? with low level hacking of _PLANES property.

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