基于两个不同的复杂标签合并标签 [英] Merging tags based on two different complex tags

问题描述

在下面的两个ASNInPO的po_nbr中，ASNInCtn下的container_id相同，而ASNInItem下的item_id不同.在这种情况下，必须合并两个ASNInPO，两个ASNInCtn必须合并到一个标签中. 这是我的输入内容:

In the below two ASNInPO's po_nbr is same container_id under ASNInCtn is same and item_id under ASNInItem is different. In this case two ASNInPO's has to be merged and two ASNInCtn's has to be merged into one tag. This is my Input:

     <?xml version = '1.0' encoding = 'UTF-8'?>
 <ASNInDesc>
    <asn_nbr>ASN-1</asn_nbr>
    <ASNInPO>
      <po_nbr>PO-2</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-2</container_id>
         <ASNInItem>
            <item_id>ITEM-2</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>
   <ASNInPO>
      <po_nbr>PO-2</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-2</container_id>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>
      </ASNInCtn>
   </ASNInPO>
  </ASNInDesc>

这是所需的输出:

<?xml version = '1.0' encoding = 'UTF-8'?>
 <ASNInDesc>
    <asn_nbr>ASN-1</asn_nbr>
    <ASNInPO>
      <po_nbr>PO-2</po_nbr>
      <ASNInCtn>
         <container_id>CONTAINER-2</container_id>
         <ASNInItem>
            <item_id>ITEM-2</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>
         <ASNInItem>
            <item_id>ITEM-3</item_id>
            <unit_qty>3</unit_qty>
         </ASNInItem>        
      </ASNInCtn>
   </ASNInPO>
 </ASNInDesc>

请帮助我解决这个问题.

Please help me in solving this.

推荐答案

由于此问题用xslt-1.0标记，因此我将发布XSLT 使用 Muenchian分组 方法的1.0解决方案. (也许有人 否则将贡献XSLT 2.0解决方案.这可能对 比较它们.)

Since this question is tagged with xslt-1.0, I'll post a XSLT 1.0 solution using the Muenchian grouping method. (Perhaps someone else will contribute a XSLT 2.0 solution. It might be instructive to compare them.)

让我们遍历样式表.

<xsl:stylesheet version="1.0" 
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" encoding="UTF-8"/>

分组1:按po_nbr的ASNInPO个元素

由于我们要按po_nbr元素分组ASNInPO元素，因此 首先定义一个 键 ，它允许检索ASNInPO 元素的po_nbr值.

Grouping 1: ASNInPO elements by po_nbr

Since we want to group ASNInPO elements by their po_nbr, let's start by defining a key which allows retrieving ASNInPO elements by their po_nbr value.

  <xsl:key name="ASNInPO-by-po_nbr" 
           match="ASNInPO" use="po_nbr"/>

然后，我们将编写一个与ASNInDesc匹配的模板.我们将做一个 元素的副本及其asn_nbr.现在我们要分组 包含的ASNInPO元素由它们的po_nbr组成.我们这样做 将模板应用于每个组中的 first ASNInPo:

Then we'll write a template which matches an ASNInDesc. We'll make a copy of the element, along with its asn_nbr. Now we want to group the contained ASNInPO elements by their po_nbr. We do this by applying templates to the first ASNInPo in each group:

  <xsl:template match="ASNInDesc">
    <xsl:copy>
      <xsl:copy-of select="asn_nbr"/>
      <xsl:apply-templates select="ASNInPO[generate-id() =
                                   generate-id(key('ASNInPO-by-po_nbr', 
                                                   po_nbr)[1])]"/>
    </xsl:copy>
  </xsl:template>

分组2:按container_id

的ASNInCtn个元素

但是在继续之前，我们需要定义另一个键.它似乎 就像我们需要将ASNInCtn元素按其container_id分组(如果不是这种情况，请参见下面的注释).

Grouping 2: ASNInCtn elements by container_id

But before we go further, we'll need to define another key. It seems like we need to group ASNInCtn elements by their container_id (see note below if this is not the case).

  <xsl:key name="ASNInCtn-by-container_id" 
           match="ASNInCtn" use="container_id"/>

我们需要以下模板中与ASNInPO相匹配的键 元素.请记住，我们在这里处理的元素将是第一个 他们的小组成员，因为我们只选择了 xsl:apply-template.

We'll need that key in the following template which matches ASNInPO elements. Remember that the elements we process here will be the first ones of their group, since we selected only those in the xsl:apply-template above.

此模板类似于我们上面编写的模板.我们复制 元素本身及其po_nbr，然后再次应用 第一个ASNInCtn元素按其分组的模板 container_id:

This template is similar to the one we wrote above. We make copy of the element itself along with its po_nbr and then again apply templates to the first ASNInCtn elements grouped by their container_id:

  <xsl:template match="ASNInPO">
    <xsl:copy>
      <xsl:copy-of select="po_nbr"/>
      <xsl:apply-templates select="key('ASNInPO-by-po_nbr', po_nbr)/
                                   ASNInCtn[generate-id() =
                                   generate-id(key('ASNInCtn-by-container_id',
                                                   container_id)[1])]"/>
    </xsl:copy>
  </xsl:template>

最后，我们编写与ASNInCtn元素匹配的模板.这 复制元素本身及其container_id，然后复制所有 相同组中的ASNInItem个元素:

Finally, we write the template which matches ASNInCtn elements. This copies the element itself, and its container_id and then copies all ASNInItem elements in the same group:

  <xsl:template match="ASNInCtn">
    <xsl:copy>
      <xsl:copy-of select="container_id"/>
      <xsl:copy-of select="key('ASNInCtn-by-container_id', 
                               container_id)/ASNInItem"/>
    </xsl:copy>
  </xsl:template>

我们完成了.

</xsl:stylesheet>

注意

该解决方案假定ASNInCtn元素具有给定 container_id只能出现在具有相同内容的ASNInPO元素中 po_nbr.如果不是这种情况，则需要为 ASNInPO对象使用po_nbr和container_id的组合.

Note

The solution assumes that the ASNInCtn element with a given container_id can only appear within ASNInPO elements with the same po_nbr. If this is not the case, then you need to adjust the key for ASNInPO objects to use a combination of po_nbr and container_id.

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