如何扩展Muenchian XML分组? [英] How to extend a Muenchian XML grouping?

问题描述

我有这个XML:

<events>
  <event name="Christmas" attendees="1"/>
  <event name="Halloween" attendees="3"/>
  <event name="Easter" attendees="2"/>
  <event name="Easter" attendees="1"/>
</events>

感谢 hr_117 的帮助，我设法做到了:/p>

Thanks to hr_117's help, I managed to do this:

<xsl:template match="data">
  <xsl:apply-templates select="events"/>
</xsl:template>

<xsl:key name="events-by-name" match="events/event" use="@name" />

<xsl:template match="events">
<xsl:for-each select="event[count(. | key('events-by-name', @name)[1]) = 1]">
    <p>
        <xsl:value-of select="concat(@name,': ')" />
        <xsl:value-of select="count(key('events-by-name', @name))" />
        <xsl:text> booking(s)</xsl:text>        
    </p>
</xsl:for-each>
</xsl:template>

</xsl:stylesheet>

哪个给我这个输出:

Christmas: 1 booking(s)
Halloween: 1 booking(s)
Easter: 2 booking(s)

但是我也该如何计算attendees，这样我就可以得到:

But how can I count the attendees as well, so that I get this:

Christmas: 1 booking(s), 1 attendee(s)
Halloween: 1 booking(s), 3 attendee(s)
Easter: 2 booking(s), 1 attendee(s)

有人可以帮忙吗?

谢谢！

推荐答案

这个怎么样?我使用sum方法尝试了一下，可以看到累加值，还添加了一些其他测试元素.

How about this? I tried it with the sum method and I can see the accumulated value, I also added some additional elements for testing.

<xsl:value-of select="concat(@name,': ')"/>
<xsl:value-of select="count(key('events-by-name', @name))"/>
<xsl:text> booking(s), </xsl:text>
<xsl:value-of select="sum(key('events-by-name', @name)/@attendees)"/>
<xsl:text> attendee(s)</xsl:text>

这篇关于如何扩展Muenchian XML分组?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！